College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.3 - Page 701: 94

Answer

See below.

Work Step by Step

For $i=1:1^2+1=1+1=2$. For $i=2:2^2+1=4+1=5$. For $i=3:3^2+1=9+1=10$. For $i=4:4^2+1=16+1=17$. For $i=5:5^2+1=25+1=26$. For $i=6:6^2+1=36+1=37$. Their sum is:$2+5+10+17+26+37=97$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.