College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Exercise Set 7.3 - Page 701: 93

Answer

$120$

Work Step by Step

The positive integers from $5$ down through $1$ are $5,4,3,2,1$. Thus for $n=5$ this means $5\cdot4\cdot3\cdot2\cdot1=120$
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