College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Concept and Vocabulary Check - Page 685: 9

Answer

$(7,-2)$

Work Step by Step

Transverse axis is vertical ( parallel to the y-axis )$:$ $\displaystyle \frac{(y-k)^{2}}{a^{2}}- \displaystyle \frac{(x-h)}{b^{2}}=1$ Center: $(h, k)$ --------- $\displaystyle \frac{(y-(-2))^{2}}{2^{2}}- \displaystyle \frac{(x-7)}{6^{2}}=1$ $(h, k)=(7,-2)$
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