College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Conic Sections - Concept and Vocabulary Check - Page 685: 10

Answer

Fill the blanks with ... 4 ... 1 ... 20

Work Step by Step

$9(x^{2}-8x+4-4)=9(x-2)^{2}-36$ (adding 4 to the first parentheses completes the square) $-16(y^{2}+2y+1-1)=-16(y-1)^{2}+16$ (adding 1 to the second parentheses completes the square) So, LHS= $9(x-2)^{2}-16(y-1)^{2}-20$ To move the $(-20)$ to the other side, we add 20 to both sides. Fill the blanks with ... 4 ... 1 ... 20
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