Answer
$\begin{vmatrix}5&4\\1&11\end{vmatrix}$
Work Step by Step
$2B+3C=2\begin{vmatrix}1&-1\\2&1\end{vmatrix}+3\begin{vmatrix}1&2\\-1&3\end{vmatrix}=\begin{vmatrix}2&-2\\4&2\end{vmatrix}+\begin{vmatrix}3&6\\-3&9\end{vmatrix}=\begin{vmatrix}2+3&-2+6\\4-3&2+9\end{vmatrix}=\begin{vmatrix}5&4\\1&11\end{vmatrix}$
