College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Test - Page 658: 10

Answer

$x=2$

Work Step by Step

In order to determine $x$, we have to compute the determinants $D,D_x$: $D=\begin{vmatrix}3&1&-2\\2&7&3\\4&-3&-1\end{vmatrix}=-21+12+12+56+27+2=88$ $D_x=\begin{vmatrix}-3&1&-2\\9&7&3\\7&-3&-1\end{vmatrix}=21+21+54+98-27+9=176$ We use Cramer's Rule to determine $x$: $x=\dfrac{D_x}{D}=\dfrac{176}{88}=2$
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