Answer
Makes sense.
Work Step by Step
If the matrix A is n$\times$n where $n > 2$,
we use the procedure outlined on p.634:
To find $A^{-1}$ for any $n\times n$ matrix $A$ for which $A^{-1}$ exists,
1. Form the augmented matrix $[A|I_{n}]$
2. Perform row operations on $[A|I_{n}]$ to obtain a matrix of the form $[I_{n}|B]$
3. Matrix $B$ is $A^{-1}$.
Step 2 is equivalent to using Gauss-Jordan elimination to change $A$ into the identity matrix.
Makes sense.
