College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.3 - Page 627: 81

Answer

sample answer: A= $\left[\begin{array}{ll} 1 & 0\\ 0 & 1 \end{array}\right]$, B= $\left[\begin{array}{ll} 1 & 2\\ 3 & 4 \end{array}\right]$

Work Step by Step

For both products to be defined, the number of columns in A must equal the number of rows in B, and the number of columns in B must equal the number of rows in A. So, take A and B to be 2$\times$2 matrices. Let one of them be A= $\left[\begin{array}{ll} 1 & 0\\ 0 & 1 \end{array}\right]$, and the other any 2$\times$2 matrix, say, B= $\left[\begin{array}{ll} 1 & 2\\ 3 & 4 \end{array}\right]$ Then AB=$\left[\begin{array}{ll} 1 & 0\\ 0 & 1 \end{array}\right]\left[\begin{array}{ll} 1 & 2\\ 3 & 4 \end{array}\right]$=$\left[\begin{array}{ll} 1 & 2\\ 3 & 4 \end{array}\right]$ and BA=$\left[\begin{array}{ll} 1 & 2\\ 3 & 4 \end{array}\right]\left[\begin{array}{ll} 1 & 0\\ 0 & 1 \end{array}\right]$=$\left[\begin{array}{ll} 1 & 2\\ 3 & 4 \end{array}\right]$
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