College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.3 - Page 627: 78

Answer

Does not make sense.

Work Step by Step

To multiply two matrices, the first must have as many columns as the other has rows. The product of an $m\times n$ matrix $A$ and an $n\times p$ matrix $B$ is an $m\times p$ matrix $AB$. So, the matrices can be multiplied. So far, makes sense. But, to obtain the element in the ith row and $j\mathrm{t}\mathrm{h}$ column of $AB$, we multiply each element in the ith row of $A$ by the corresponding element in the $j\mathrm{t}\mathrm{h}$ column of $B$ and add the products. (Not simply multiply corresponding elements) Does not make sense.
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