College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.2 - Page 539: 36

Answer

$x=3.5$ $y=1.5$ $z=0.75$

Work Step by Step

We will denote price of a gallon of milk by $x$, price of bottle of water by $y$ and price of snack-size bag of chips by $z$. We are given the system: $\begin{cases} x+7y+4z=17\\ y=2z\\ x=y+2 \end{cases}$ We substitute $y$ in places of $2z$ in the first equation. substract $y$ from both sides in the second equation to get the variables on one side of the equation. $\begin{cases} x+7y+2(2z)=x+7y+2y=xx+9y=17\\ x-y=y-y+2=x-y=2 \end{cases}$ We will use the addition method. Multiply the Equation 2 by $9$ and add it to Equation 1. $\begin{cases} x+9y=17\\ 9x-9y=18 \end{cases}$ $10x=35$ $x=3.5$ Substitute the value of $x$ in the Equation $x=y+2$ to determine $y$: $3.5=y+2$ $1.5=y$ Substitute the values of $x, y$ in Equation 1 of the given system to find $z$: $x+7y+4z=17$ $(3.5)+7(1.5)+4z=17$ $3.5+10.5+4z=17$ $4z=17-14$ $z=0.75$ The solution is $(x=3.5,y=1.5,z=0.75)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.