College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 528: 53

Answer

$y=x-4$ $y=-\displaystyle \frac{1}{3}x+4$

Work Step by Step

A graphical solution to a system of linear equations is a point of intersection of two lines. From the graph, we have two lines passing through the point (6,2), with equations $ x-y=4\qquad$and$\quad x+3y=12$ Slope-intercept form: solve each equation for $y$: $\left[\begin{array}{lll} x-y=4 & & x+3y=12\\ -y=-x+4 & & 3y=-x+12\\ y=x-4 & & y=-\frac{1}{3}x+4 \end{array}\right]$ The system: $y=x-4$ $y=-\displaystyle \frac{1}{3}x+4$
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