## College Algebra (6th Edition)

$y=x-4$ $y=-\displaystyle \frac{1}{3}x+4$
A graphical solution to a system of linear equations is a point of intersection of two lines. From the graph, we have two lines passing through the point (6,2), with equations $x-y=4\qquad$and$\quad x+3y=12$ Slope-intercept form: solve each equation for $y$: $\left[\begin{array}{lll} x-y=4 & & x+3y=12\\ -y=-x+4 & & 3y=-x+12\\ y=x-4 & & y=-\frac{1}{3}x+4 \end{array}\right]$ The system: $y=x-4$ $y=-\displaystyle \frac{1}{3}x+4$