College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 528: 50

Answer

$(\frac{1}{2a}, \frac{1}{b})$

Work Step by Step

Multiply 4ax + by = 3 by 5 20ax + 5by = 15 Subtract 6ax + 5by = 8 from 20ax + 5by = 15 20ax + 5by = 15 6ax + 5by = 8 You get: 14ax = 7 x = $\frac{1}{2a}$ Plug x into 4ax + by = 3 4a($\frac{1}{2a}$) + by = 3 2 + by = 3 by = 1 y = $\frac{1}{b}$
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