College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Summary, Review, and Test - Test - Page 586: 1

Answer

$(1,-3)$

Work Step by Step

We are given the system: $\begin{cases} x=y+4\\ 3x+7y=-18 \end{cases}$ We will use the substitution method. Equation 1 is solved for $x$. We substitute the expression of $x$ in Equation 2 to eliminate $x$ and determine $y$: $\begin{cases} x=y+4\\ 3(y+4)+7y=-18 \end{cases}$ $3(y+4)+7y=-18$ $3y+12+7y=-18$ $10y+12=-18$ $10y=-30$ $y=-3$ Substitute the value of $y$ in the expression of $x$ to determine $x$: $x=y+4$ $x=-3+4$ $x=1$ The system's solution is: $(1,-3)$
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