Answer
$\dfrac{\ln 3}{10}\approx 11\%$
Work Step by Step
We are given:
$A=18000$
$P=6000$
$t=10$
Determine the rate $r$ using the formula:
$A=Pe^{rt}$
$18000=6000e^{10r}$
$\dfrac{18000}{6000}=e^{10r}$
$3=e^{10r}$
$\ln 3=\ln e^{10r}$
$\ln 3=10r$
$r=\dfrac{\ln 3}{10}\approx 0.11=11\%$