Answer
No solution
Work Step by Step
We are given the system:
$\begin{cases}
\dfrac{x}{12}-y=\dfrac{1}{4}\\
4x-48y=10
\end{cases}$
We will use the substitution method. Solve Equation 1 for $y$ and substitute the expression of $y$ in Equation 2 to eliminate $y$ and determine $x$:
$\begin{cases}
y=\dfrac{x}{12}-\dfrac{1}{4}\\
4x-48\left(\dfrac{x}{12}-\dfrac{1}{4}\right)=10
\end{cases}$
$4x-48\left(\dfrac{x}{12}-\dfrac{1}{4}\right)=10$
$4x-4x+12=10$
$12=10$
We got a false statement, therefore the system has no solution.