College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Mid-Chapter Check Point - Page 561: 2

Answer

$x = 1$ $ y = -2$

Work Step by Step

$3x + 4y - (-5) $ $2x -3y -8$ Rearrange $3x + 4y = -5 $ -> equation 1 $2x -3y = 8$ -> equation 2 Multiply equation 1 by number the 2 and multiply equation 2 by number the 3 $(3x + 4y = -5) \times 2$ $(2x -3y = 8) \times 3$ $6x + 8y = -10$ $6x -9y = 24$ subtract $6x + 8y = -10$ - $6x -9y = 24$ $=0 + 17y = - 34$ $ y = -\frac{34}{17}$ $ y = -2$ Replace y in equation 1 $(3x + (4 \times-2) = -5 $ $= 3x - 8 = -5$ $= 3x = -5 +8 $ $ =3x = 3$ $x = 1$
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