College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 513: 93

Answer

$6.5e^{-0.844x}$

Work Step by Step

We know that $e^{\ln{a}}=a$. So here $y=6.5\cdot0.43^x=6.5e^{\ln{0.43}x}=6.5e^{-0.844x}$
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