College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 513: 92

Answer

$73e^{0.956x}$

Work Step by Step

We know that $e^{\ln{a}}=a$. So here $y=73\cdot2.6^x=73e^{\ln{2.6}x}=73e^{0.956x}$
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