College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Summary, Review, and Test - Review Exercises - Page 438: 81

Answer

$16$ hours

Work Step by Step

Since the time required to assemble computers varies DIRECTLY with the number of computers assembled and INVERSELY with the number of workers, we can express this in the following manner: $$t=\frac{kc}{w}$$ where $t$ = time required to assemble computers, $c$ is the number of computers assembled, $w$ is the number of workers, and $k$ is a proportionality constant. Since we know that, when $c = 30$ and $w=6$, then $t=10$, we can calculate $k$: $$t = \frac{kc}{w}$$ $$\frac{tw}{c} = k$$ $$\frac{(10)(6)}{30} = k = 2$$ and finally answer the question: $$t = 2(\frac{40}{5}) = 16$$
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