College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Summary, Review, and Test - Review Exercises - Page 438: 78

Answer

$1,600ft$

Work Step by Step

Since the distance a body falls is DIRECTLY proportional to the square of the time of the fall, we can express this with the following equation: $$d =kt^{2}$$ where $d$ is the distance, $k$ is a proportionality constant, and $t^{2}$ is the square of the time of the fall. Since we know that, when $d=144ft$, $t=3$, we can calculate $k$: $$k = \frac{d}{t^{2}}$$ $$k = \frac{144}{3^{2}} = \frac{144}{9} = 16$$ and finally answer the question: $$d = 16(10^{2}) = 16(100) = 1,600ft$$
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