Answer
domain : $\{\ x \ |\ \ x\neq-6, \ x\neq 2 \ \}$
interval notation: $(-\infty,-6)\cup(-6,2)\cup(2,\infty)$
Work Step by Step
See example 1.
Division by 0 is undefined, so
f(x) will be defined for all real numbers except for
the number(s) x that yield zero in the denominator:
$(x-2)(x+6)=0$
$x=2$ or $x=-6\qquad $(zero product principle)
domain : $\{\ x \ |\ \ x\neq-6, \ x\neq 2 \ \}$
interval notation: $(-\infty,-6)\cup(-6,2)\cup(2,\infty)$
