College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.4 - Page 388: 66

Answer

Basic reason: zero product principle. please see "step by step for details"

Work Step by Step

The reason is: the zero product principle. (in short: if one factor is 0, the whole product is zero) (also, if the product is zero, then (at least) one of the factors is zero) The polynomial equation $f(x)=0$ has n factors on the LHS. For the equation $f(x)=0$ to be satisfied, a factor on the LHS must be 0. There are n factors, and any one may be 0, so the solution set is $\{c_{1}, c_{2}, ..., c_{n}\}$ which has n members. The above set represents the n zeros of f(x), that is the n values of x for which f(x)=0. Each of the n zeros of the polynomial f(x) is a root (solution) of the equation f(x)=0.
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