## College Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.1 - Page 347: 103

See below.

#### Work Step by Step

By plugging in $x=2$ and $x=3$ into $f(x)=x^3-2x-5$, we get $f(2)=2^3-2\cdot2-5=8-4-5=-1$ and $f(3)=3^3-2\cdot3-8=27-6-5=16$ Thus by the Intermediate Value Theorem, the continuous graph must cross the x-axis somewhere between $x=2$ and $x=3$.

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