## College Algebra (6th Edition)

Fill the blanks in with : 9 ... $(3x-5)$ ... $9$ ... ... $3x-5+\displaystyle \frac{9}{2x+1}$
Long Division of Polynomials 1. Arrange ... 2. Divide ... 3. Multiply ... 4. Subtract the product from the dividend. 5. Bring down the next term in the original dividend and write it next to the remainder to form a new dividend. 6. Use this new expression as the dividend and repeat this process until the remainder can no longer be divided. This will occur when the degree of the remainder (the highest exponent on a variable in the remainder) is less than the degree of the divisor. ---------- So, subtracting the product $(-10-5)$ from the dividend $(-10x+4)$ we obtain $+9=9$ Thus, the quotient is $(3x-5)$remainder is $9.$ The answer to $(6x^{2} -7x+4)\div(2x+1)$ is written as $3x-5+\displaystyle \frac{9}{2x+1}$