Answer
y+$\frac{1}{6}$x+3=0
Work Step by Step
6x-y-4=0
y=6x-4
Since our desired line is perpendicular to the line with the above equation, our desired slope must be -$\frac{1}{6}$
y-y$_1$=m(x-x$_1$)
y+1=-$\frac{1}{6}$(x+12)
y+1=-$\frac{1}{6}$x-2
y+$\frac{1}{6}$x+1+2=0
y+$\frac{1}{6}$x+3=0
