Answer
y-6=-3(x+3)
y=-3x-3
Work Step by Step
The desired line is perpendicular to a line with a slope of $\frac{1}{3}$, therefore our desired slope is m=-3
y-y$_1$=m(x-x$_1$)
y-6=-3(x+3)
y=-3x-9+6
y=-3x-3
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Summary, Review, and Test - Review Exercises - Page 324: 38
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