College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Cumulative Review Exercises (Chapters 1-2) - Page 328: 16

Answer

$x=-7$ or $x=-3$

Work Step by Step

The exercise is asking us to identify the zeros of $f(g(x))$: $$f(g(x)) = 4 - (x + 5)^{2}$$ $$f(g(x)) = 4 - (x^{2} + 10x + 25)$$ $$f(g(x)) = 4 - x^{2} - 10x - 25$$ $$f(g(x)) = -x^{2} - 10x - 21$$ Finding the zeros of this function: $$f(g(x)) = 0 = -x^{2} - 10x - 21$$which is the same as: $$0 = x^{2} + 10x + 21$$ Since two factors of 21 that, when added, give 10 are 3 and 7, we can factorize the function into: $$0 = (x+ 7)(x+3)$$ and solve: $0 = x+7$ or $0=x+3$ $0-7=x$ or $0-3=x$ $-7=x$ or $-3=x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.