College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.7 - Page 310: 63

Answer

$g(f[h(1)]) = 11$

Work Step by Step

$g(f[h(1)])$ $h(x) = x^{2} + x + 2$ $h(1) = (1)^{2} + (1) + 2$ $= 1 + 1 + 2$ $= 2 + 2$ $= 4$ $f(4) = 2(4) - 5$ $= 8 - 5$ $= 3$ $g(3) = 4(3) - 1$ $= 12 - 1$ $= 11$ $g(f[h(1)]) = 11$
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