College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.7 - Page 310: 61

Answer

$f^{-1}(1)= 3$

Work Step by Step

Let $y = f(x)$ $y = 2x - 5$ $x = 2y - 5$ $x + 5 = 2y$ $y = \frac{x+5}{2}$ $f^{-1}(x)= \frac{x+5}{2}$ $f^{-1}(1)= \frac{(1)+5}{2}$ $= \frac{6}{2}$ $=3$
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