College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.6 - Page 297: 12



Work Step by Step

Making $x=−2,2$ results in an undefined function, so those values are excluded from the domain. $g(x)=\frac{1}{x^2+4}-\frac{1}{x^2-4}$ $g(x)=\frac{1}{x^2+4}-\frac{1}{(x+2)(x-2)}$ $(-∞,-2)∪(-2,2)∪(2,∞)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.