Answer
0
Work Step by Step
Calculate each individual term:
$|f(1)-f(0)|=|-4-(-1)|$
$=|-4+1|=|-3|=3$
$[g(1)]^{2}=(-3)^{2}=9$
$g(1)\div f(-1)\cdot g(2)=(-3)\div 3\cdot(-6)$
$=-1\cdot(-6)=6$
$|f(-1)-f(0)|-[g(1)]^{2}+g(1)\div f(-1)g(2)=$
$=3-9+6$
$=-6+6$
$=0$
