College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.1 - Page 226: 96



Work Step by Step

Calculate each individual term: $|f(1)-f(0)|=|-4-(-1)|$ $=|-4+1|=|-3|=3$ $[g(1)]^{2}=(-3)^{2}=9$ $g(1)\div f(-1)\cdot g(2)=(-3)\div 3\cdot(-6)$ $=-1\cdot(-6)=6$ $|f(-1)-f(0)|-[g(1)]^{2}+g(1)\div f(-1)g(2)=$ $=3-9+6$ $=-6+6$ $=0$
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