## College Algebra (6th Edition)

$-38$
Calculate each individual term: $\sqrt{f(-1)-f(0)}=\sqrt{3-(-1)}=\sqrt{4}=2,$ $[g(2)]^{2}=(-6)^{2}=36$ $f(-2)\div g(2)g(-1)=6\div(-6)\cdot 4=-1\cdot 4=-4$ $\sqrt{f(-1)-f(0)}-[g(2)]^{2}+f(-2)\div g(2)g(-1)=$ $= 2 -36 +(-4)$ $=-34-4$ $=-38$