Answer
$(2-\sqrt{-3})^{2}=1-4\sqrt{3}i$
Work Step by Step
$(2-\sqrt{-3})^{2}$
Evaluate the power:
$(2-\sqrt{-3})^{2}=2^{2}-(2)(2)(\sqrt{-3})+(\sqrt{-3})^{2}=...$
Simplify:
$...=4-4\sqrt{-3}-3=1-4\sqrt{-3}=...$
Substitute $\sqrt{-3}$ by $\sqrt{3}i$:
$...=1-4\sqrt{3}i$
