College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Mid-Chapter Check Point - Page 166: 38

Answer

a. $6$ years. b. See point on the graph.

Work Step by Step

a. Given $P=-10x^2+475x+3500$. let $P=5990$, we have $-10x^2+475x+3500=5990$ or $2x^2-95x+498=0$ which can be factored as $(x-6)(2x-83)=0$. As $0\leq x\leq 12$, we have $x=6$ years. b. The coordinates of the point are $(6,5990)$ and we can mark the point on the curve as shown in the figure.
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