College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.7 - Page 199: 158

Answer

$10-x$

Work Step by Step

$12\cdot(\frac{x+2}{4}-\frac{x-1}{3})=3(x+2)-4(x-1)=3x+6-4x+4=10-x$
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