College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.7 - Page 199: 153

Answer

The problem with this argument is that when you multiply both sides by (y-x) you are multiplying by a negative number (-x) therefore you must switch the direction of the sign. The correct solution is y$\lt$x.

Work Step by Step

2$\gt$1 2(y-x)$\lt$1(y-x) 2y-2x$\lt$y-x y$\lt$x
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