College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 181: 136

Answer

$\frac{2}{5}$, $\frac{1}{2}$

Work Step by Step

Step 1. Let $u=\sqrt {5-\frac{2}{x}}$, we have $u^2=u$ or $u(u-1)=0$ which gives $u=0, 1$ Step 2. For $u=0$, we have $5-\frac{2}{x}=0$ and $x=\frac{2}{5}$ Step 2. For $u=1$, we have $5-\frac{2}{x}=1$ and $x=\frac{1}{2}$
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