Answer
$-(0)^4+4(0)^3-4(0)^2=0$
$0=0$
$-(2)^4+4(2)^3-4(2)^2=0$
$-16+32-16=0$
$0=0$
Work Step by Step
$-x^4+4x^3-4x^2=0$
When graphing, the $x$-intercepts are $0$ and $2$. Simply plug these values into the equation to check the solutions.
$-(0)^4+4(0)^3-4(0)^2=0$
$0=0$
$-(2)^4+4(2)^3-4(2)^2=0$
$-16+32-16=0$
$0=0$
