## College Algebra (11th Edition)

$\{x|x\ne-\frac{3}{2},5\}$
In this rational expression, the solution to the denominator cannot be zero. Solve the denominator for x by setting each factor to 0. These answers are restricted from the domain. $(2x+3)(x-5)=0$ $x=-\frac{3}{2}$ or $x=5$ Put the domain in set builder notation. $\{x|x\ne-\frac{3}{2},5\}$