Answer
$\{x|x\ne-\frac{1}{2},1\}$
Work Step by Step
In this rational expression, the solution to the denominator cannot be zero. Solve the denominator for x. This is the restriction from the domain.
$(4x+2)(x-1)=0$
$x=-\frac{1}{2}$ or $x=1$
Put the domain in set notation.
$\{x|x\ne-\frac{1}{2},1\}$
