Answer
$(2p^2+3)(3p^2-1)$
Work Step by Step
The two numbers whose product is $ac=
6(-3)=-18
$ and whose sum is $b=
7
$ are $\{
9,-2
\}$. Using these two numbers to decompose the middle term of the expression, $
6p^4+7p^2-3
,$ then the factored form is
\begin{array}{l}\require{cancel}
6p^4+9p^2-2p^2-3
\\\\=
(6p^4+9p^2)-(2p^2+3)
\\\\=
3p^2(2p^2+3)-(2p^2+3)
\\\\=
(2p^2+3)(3p^2-1)
.\end{array}
