College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 40: 101

Answer

not factorable

Work Step by Step

Although both terms of the given expression, $ 144z^2+121 ,$ are perfect squares, the operator between them is a '+' and not a '-'. Hence, the given expression is $\text{ not factorable }$ over the set of integers.
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