College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 38: 43

Answer

2$(4a + 3b)^{2}$

Work Step by Step

1. Factor out GCF (2): 2(16$a^{2}$ + 24ab + 9$b^{2}$) 2. Factor expression inside parentheses: 2(4a + 3b)(4a + 3b) = 2$(4a + 3b)^{2}$
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