College Algebra (11th Edition)

$2\sqrt[3]{2}$
Getting the factor that is a perfect root of the index, the given expression, $\sqrt[3]{16} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{8\cdot2} \\\\= \sqrt[3]{(2)^3\cdot2} \\\\= 2\sqrt[3]{2} .\end{array}