## College Algebra (11th Edition)

$10\sqrt{2}$
Getting the factor that is a perfect root of the index, the given expression, $\sqrt{200} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt{100\cdot2} \\\\= \sqrt{(10)^2\cdot2} \\\\= 10\sqrt{2} .\end{array}