College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.6 - Counting Theory - 7.6 Exercises - Page 679: 24

Answer

$863,040$

Work Step by Step

Using $_nP_r=\dfrac{n!}{(n-r)!},$ the given expression, $ _{32}P_{4} ,$ evaluates to \begin{array}{l}\require{cancel} =\dfrac{32!}{(32-4)!} \\\\= \dfrac{32!}{28!} \\\\= \dfrac{32(31)(30)(29)(\cancel{28!})}{\cancel{28!}} \\\\= 863,040 \end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.