College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.2 - Arithmetic Sequences and Series - 7.2 Exercises: 47

Answer

$S_{60}=3,660$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To find the sum of the first $ 60 $ positive even integers, use the formula for finding the sum of $n$ terms that form an arithmetic sequence. $\bf{\text{Solution Details:}}$ The sequence described by "the first $60$ positive even integers," is an arithmetic sequence with $a_1=2, d=2,$ and $n=60.$ Using the formula for the sum of the first $n$ terms of an airthmetic sequence, which is given by $ S_n=\dfrac{n}{2}[2a_1+(n-1)d] ,$ then \begin{array}{l}\require{cancel} S_{60}=\dfrac{60}{2}[2(2)+(60-1)2] \\\\ S_{60}=30[4+59(2)] \\\\ S_{60}=30[4+118] \\\\ S_{60}=30[122] \\\\ S_{60}=3,660 .\end{array}
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