Answer
$a_5=-162$
Work Step by Step
The first $n$ terms of a geometric sequence can be found as: $ a_n=a_1 \cdot r^{n-1}$.
where, $r$ is the common ratio, $r$ and can be computed as the quotient of a term and the term preceding it.
From the given sequence, we have: $$a_1=-2;r=3 $$
Plug the given values to obtain in above formula to evaluate $a_5$( fifth term): $$a_{5}=a_1\cdot r^{n-1}\\ a_5=(-2) 3^{5-1}\\a_5=(-2) \cdot (3)^4\\
a_5=-2(81)
a_5=-162$$
Therefore, the fifth term of an geometric sequence is: $a_5=-162$.
