College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Review Exercises - Page 698: 15

Answer

$-x+61$

Work Step by Step

The nth term of an arithmetic sequence can be found as: $a_n=a_1+(n-1)d$. where, $a_1$ is the first term and $d$ is the common difference(is the difference between a term and the term proceeding it), that is, $d=a_n-a_{n-1}$ From the given series, we have: $a_1=6x-9$ $d=a_2-a_1=5x+1-(6x-9)=-x+10$. Substitute these values in the formula above and evaluate for $n=8$( eighth term). $a_8=6x-9+(8-1)(-x+10) \\ a_8=6x-9+7(-x+10)\\ a_8=6x-9-7x+70\\ a_8=-x+61$ Therefore, the eighth term of an arithmetic sequence is: $-x+61$
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