College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.7 - Properties of Matrices - 5.7 Exercises - Page 554: 39

Answer

$\begin{bmatrix} -9 &3\\6&0\end{bmatrix} $

Work Step by Step

When we multiply a scalar $k$ with a matrix $A$, then the product will be the matrix $kA$, each of whose elements is $k$ times the corresponding element of $A$. Thus, to find $\frac{3}{2}B$, we have to multiply $\frac{3}{2}$ to each element of $B$ to obtain: \begin{align*} \frac{3}{2}B&= \frac{3}{2}\begin{bmatrix} -6 &2\\4&0\end{bmatrix}\\ \\&=\begin{bmatrix} (\frac{3}{2})(-6) &(\frac{3}{2})(2)\\(\frac{3}{2})(4)&(\frac{3}{2})(0)\end{bmatrix}\\ \\&=\begin{bmatrix} -9 &3\\6&0\end{bmatrix} \end{align*}
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